Collections:
JSON_REPLACE() - Replacing JSON Child Members
How to replace child members of a JSON (JavaScript Object Notation) value using the JSON_REPLACE() function?
✍: FYIcenter.com
JSON_REPLACE(json, path1, val1, path2, val2, ...) is a MySQL built-in function that
replaces child members of a JSON value at given locations.
Each path-value argument pair specifies existing member locations
and replace-by values. Non-existing member locations are ignored.
The path argument uses the "$", "$.key" or "$[i]" format.
The value can be a JSON scalar (String, Number, Boolean, or Null),
a JSON array, or a JSON object.
JSON scalars can be specified as literals of MySQL equivalent data types. For example:
SET @j = '["a", {"b": [1, 2]}, [3, 4]]'; SELECT JSON_REPLACE(@j, '$[0]', 10, '$[2]', '[true, false]'); -- +-------------------------------------------------------+ -- | JSON_REPLACE(@j, '$[0]', 10, '$[2]', '[true, false]') | -- +-------------------------------------------------------+ -- | [10, {"b": [1, 2]}, "[true, false]"] | -- +-------------------------------------------------------+ SELECT JSON_REPLACE(@j, '$[1].b', '[true, false]', '$[9]', 'End'); -- +------------------------------------------------------------+ -- | JSON_REPLACE(@j, '$[1].b', '[true, false]', '$[9]', 'End') | -- +------------------------------------------------------------+ -- | ["a", {"b": "[true, false]"}, [3, 4]] | -- +------------------------------------------------------------+ SELECT JSON_REPLACE(@j, '$', '[true, false]'); -- +----------------------------------------+ -- | JSON_REPLACE(@j, '$', '[true, false]') | -- +----------------------------------------+ -- | "[true, false]" | -- +----------------------------------------+
However, JSON arrays and JSON objects need to be constructed with CAST(), JSON_ARRAY(), or JSON_OBJECT() functions. For example:
SET @j = '["a", {"b": [1, 2]}, [3, 4]]'; SELECT JSON_REPLACE(@j, '$[2]', CAST('[true, false]' AS JSON)); -- +---------------------------------------------------------+ -- | JSON_REPLACE(@j, '$[2]', CAST('[true, false]' AS JSON)) | -- +---------------------------------------------------------+ -- | ["a", {"b": [1, 2]}, [true, false]] | -- +---------------------------------------------------------+ SELECT JSON_REPLACE(@j, '$[2]', JSON_ARRAY(true, false)); -- +---------------------------------------------------+ -- | JSON_REPLACE(@j, '$[2]', JSON_ARRAY(true, false)) | -- +---------------------------------------------------+ -- | ["a", {"b": [1, 2]}, [true, false]] | -- +---------------------------------------------------+ SELECT JSON_REPLACE(@j, '$[2]', JSON_OBJECT('PI',3.14)); -- +--------------------------------------------------+ -- | JSON_REPLACE(@j, '$[2]', JSON_OBJECT('PI',3.14)) | -- +--------------------------------------------------+ -- | ["a", {"b": [1, 2]}, {"PI": 3.14}] | -- +--------------------------------------------------+
Reference information of the JSON_REPLACE() function:
JSON_REPLACE(json, path1, val1, path2, val2, ...): modjson Replaces child members of a JSON value at given locations, which are specified by path arguments in the "$", "$.key" or "$[i]" format. Arguments, return value and availability: json: Required. The JSON value to be updated. path1, val1, path2, val2, ...: One or more JSON path-value pairs to be processed. modjson: Return value. The updated JSON value. Available since MySQL 5.7.
Related MySQL functions:
⇒ JSON_SCHEMA_VALID() - JSON Schema Validation
⇐ JSON_REMOVE() - Removing JSON Child Members
2023-12-11, 789🔥, 0💬
Popular Posts:
How To Convert Numeric Expression Data Types using the CAST() Function in SQL Server Transact-SQL? I...
Where Is the Export Dump File Located in Oracle? If you are not specifying the dump directory and fi...
What To Do If the StartDB.bat Failed to Start the XE Instance in Oracle? If StartDB.bat failed to st...
Where to find answers to frequently asked questions on Storage Engines: MyISAM, InnoDB and BDB in My...
How To Calculate DATETIME Value Differences Using the DATEDIFF() Function in SQL Server Transact-SQL...