Collections:
JSON_ARRAY_APPEND() - Appending Value to JSON Array
How to append a new JSON value to a given JSON (JavaScript Object Notation) array using the JSON_ARRAY_APPEND() function?
✍: FYIcenter.com
JSON_ARRAY_APPEND(json, path1, val1, path2, val2, ...) is a MySQL built-in function that
appends new JSON values to child arrays of a given JSON value.
Each path-value argument pair specifies which JSON child array to be appended
and what JSON value to append.
The path argument uses the "$", "$.key" or "$[i]" format.
The value can be a JSON scalar (String, Number, Boolean, or Null),
a JSON array, or a JSON object.
JSON scalars can be specified as literals of MySQL equivalent data types. For example:
SET @j = '["a", ["b", "c"], "d"]';
SELECT JSON_ARRAY_APPEND(@j, '$', 'end');
-- +-----------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$', 'end') |
-- +-----------------------------------+
-- | ["a", ["b", "c"], "d", "end"] |
-- +-----------------------------------+
SELECT JSON_ARRAY_APPEND(@j, '$[1]', 1);
-- +----------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$[1]', 1) |
-- +----------------------------------+
-- | ["a", ["b", "c", 1], "d"] |
-- +----------------------------------+
SET @j = '{"a": 1, "b": [2, 3], "c": 4}';
SELECT JSON_ARRAY_APPEND(@j, '$.b', 'x');
-- +------------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$.b', 'x') |
-- +------------------------------------+
-- | {"a": 1, "b": [2, 3, "x"], "c": 4} |
-- +------------------------------------+
However, JSON arrays and JSON objects need to be constructed with CAST(), JSON_ARRAY(), or JSON_OBJECT() functions. For example:
SET @j = '["a", ["b", "c"], "d"]';
SELECT JSON_ARRAY_APPEND(@j, '$', CAST('[1,2,3]' AS JSON));
-- +-----------------------------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$', CAST('[1,2,3]' AS JSON)) |
-- +-----------------------------------------------------+
-- | ["a", ["b", "c"], "d", [1, 2, 3]] |
-- +-----------------------------------------------------+
SELECT JSON_ARRAY_APPEND(@j, '$', JSON_ARRAY(1,2,3));
-- +-----------------------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$', JSON_ARRAY(1,2,3)) |
-- +-----------------------------------------------+
-- | ["a", ["b", "c"], "d", [1, 2, 3]] |
-- +-----------------------------------------------+
SELECT JSON_ARRAY_APPEND(@j, '$', JSON_OBJECT('End','Yes'));
-- +------------------------------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$', JSON_OBJECT('End','Yes')) |
-- +------------------------------------------------------+
-- | ["a", ["b", "c"], "d", {"End": "Yes"}] |
-- +------------------------------------------------------+
Note that if the path argument points to scalar element, it will be converted into array first and appended with the new value. For example:
SET @j = '["a", ["b", "c"], "d"]';
SELECT JSON_ARRAY_APPEND(@j, '$[1][0]', 3);
-- +-------------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$[1][0]', 3) |
-- +-------------------------------------+
-- | ["a", [["b", 3], "c"], "d"] |
-- +-------------------------------------+
SET @j = '{"a": 1}';
SELECT JSON_ARRAY_APPEND(@j, '$', 'z');
-- +---------------------------------+
-- | JSON_ARRAY_APPEND(@j, '$', 'z') |
-- +---------------------------------+
-- | [{"a": 1}, "z"] |
-- +---------------------------------+
Reference information of the JSON_ARRAY_APPEND() function:
JSON_ARRAY_APPEND(json, path1, val1, path2, val2, ...): modjson
Appends new JSON values to child arrays of a given JSON value.
Each path-value argument pair specifies which JSON child array
to be appended and what JSON value to append.
The path argument uses the "$", "$.key" or "$[i]" format.
Arguments, return value and availability:
json: Required. The JSON value to be updated.
path1, val1, path2, val2, ...: One or more JSON path-value pairs
to be processed.
modjson: Return value. The updated JSON value.
Available since MySQL 5.7.
⇒ JSON_ARRAY_INSERT() - Inserting Value to JSON Array
⇐ JSON_ARRAY() - Creating JSON Array
2023-12-12, 1104🔥, 0💬
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